def solution(history, keyword, option = [["W","F"]]):
answer = []
if option[0][1] == 'F': answer.append("empty")
else:
for i in range(len(history)):
if history[i].count(keyword) >= 1: answer.append(history[i])
else : answer.append("empty")
return answer
solution(["hello i am david",
"hello kail",
"hi tina"], [['W','T']],"hello")
SQL
복사